x^2+4x=3x-12

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Solution for x^2+4x=3x-12 equation: 



x^2+4x=3x-12

We move all terms to the left:

x^2+4x-(3x-12)=0

We get rid of parentheses

x^2+4x-3x+12=0

We add all the numbers together, and all the variables

x^2+x+12=0

a = 1; b = 1; c = +12;
Δ = b2-4ac
Δ = 12-4·1·12
Δ = -47
Delta is less than zero, so there is no solution for the equation

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